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64b^2=376b-280
We move all terms to the left:
64b^2-(376b-280)=0
We get rid of parentheses
64b^2-376b+280=0
a = 64; b = -376; c = +280;
Δ = b2-4ac
Δ = -3762-4·64·280
Δ = 69696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{69696}=264$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-376)-264}{2*64}=\frac{112}{128} =7/8 $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-376)+264}{2*64}=\frac{640}{128} =5 $
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